QUICK REVIEW
Quick Review — Thermodynamic Processes and PV Diagrams — Algebra-Based
Refresh the essential ideas and relationships for Thermodynamic Processes and PV Diagrams in just a few minutes.
TIME
5–10 minutes
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A rapid refresh
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Key ideas refreshed
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Course Alignment
This Physics Sensei Unit Review is an independent learning resource. Use it to reinforce key concepts, prepare for homework, or review before a quiz or exam.
RESOURCE: Physics Sensei Unit Review | UNIT ID: THM-U09 | TOPIC: Thermodynamic Processes and PV Diagrams | COURSE LEVEL: Algebra-Based
BEST USED ✓ After learning the unit ✓ Before starting homework ✓ Before a quiz or exam
Your Review Plan
Complete these four stages to quickly refresh the essential ideas and confirm you're ready to continue.
4 Stages • Approximately 5–10 minutes.
Quick Recall
Let's quickly refresh what you already know. These short recall activities will help you bring the most important ideas back to mind before reviewing them.
QUICK RECALL
Recall Activity
Complete the three statements from memory before revealing the answer.
Write the defining condition for isochoric, isobaric, isothermal, and adiabatic processes. Then write the work for a constant-pressure volume change.
Reveal Answers
Isochoric: ΔV = 0. Isobaric: ΔP = 0. Isothermal: ΔT = 0. Adiabatic: Q = 0. At constant pressure, W = PΔV.
Why it works: The constraint identifies the process, and W = PΔV is the rectangular area under a horizontal P–V path.
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Essential Idea
Take one last look at the most important concept from this unit. If you remember this idea, the rest will come back much more easily.
ESSENTIAL IDEA
Use the constraint first, then the P–V area
Thermodynamic process equations become simpler once you identify what is held fixed. On a P–V diagram, work by the gas is the signed area under the path. For a horizontal constant-pressure segment, that area is a rectangle.
W = PΔV (constant pressure); P₁V₁ = P₂V₂ (isothermal ideal gas)
Example: At P = 1.5 × 10⁵ Pa, expansion from 2.0 L to 5.0 L gives ΔV = 3.0 × 10⁻³ m³ and W = 450 J.
Sensei note: Convert liters to cubic meters before multiplying pressure by volume change: 1 L = 10⁻³ m³.
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Confidence Check
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CONFIDENCE CHECK
Constant-pressure work
Answer all three without notes.
A gas expands at 2.0 × 10⁵ Pa from 1.0 L to 4.0 L. What is W?
Reveal Answers
ΔV = 3.0 × 10⁻³ m³, so W = PΔV = 600 J.
Why it works: A rightward horizontal path is constant-pressure expansion, so its rectangular P–V area is positive.
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