FOCUSED REVIEW

Focused Review: Simple Harmonic Motion — Algebra-Based

Reinforce the highest-leverage ideas and problem-solving tools for Simple Harmonic Motion.

TIME

15–20 minutes

BEST FOR

Focused reinforcement

FINISH WITH

Greater confidence

After this focused review, you’ll be able to...

explain the essential relationships, apply the key methods, and continue with greater confidence.

Choose how you want to review

Course Alignment

This bundle follows the approved independent Physics Sensei unit specification. Use it to reinforce key concepts, prepare for coursework, or review before an assessment.

RESOURCE: Independent Physics Sensei Unit Review

UNIT: Mechanics • Unit MEC-U09

TOPIC: Simple Harmonic Motion

COURSE LEVEL: Algebra-Based

BEST USED

✓ After studying the unit

✓ Before starting homework

✓ Before a quiz or exam

Your Review Plan

Complete these six focused stages in order. Each stage reinforces the highest-leverage ideas and prepares you for a final confidence check.

6 Stages • Approximately 15–20 minutes

Warm-Up Check

Refresh key ideas.

Core Concepts

Reinforce the essentials.

Guided Practice

Strengthen key skills.

Confidence Check

Confirm your understanding.

Summary

Remember the essentials.

Next Step

Choose your next step.

Warm-Up Check

Distance is center-to-center and field follows an inverse-square rule. Gravity remains substantial in orbit; the support force is nearly absent.

WARM-UP 1

Key Ideas

Recall the defining SHM rule.

Write the spring restoring-force equation.
Reveal Answer
F = −kx.

Why it works: The essential test is a restoring acceleration proportional to −displacement.

WARM-UP 2

Common Mistakes

Check the cycle quantities.

Connect T, f, and ω.
Reveal Answer
f = 1/T and ω = 2πf = 2π/T.

Why it works: Displacement, velocity, and acceleration have fixed phase relationships in ideal SHM.

WARM-UP 3

Quick Application

Recall the energy and pendulum limits.

Write total spring-oscillator energy.
Reveal Answer
E = ½mv² + ½kx² = ½kA².

Why it works: Energy and the small-angle approximation provide two fast ways to check an SHM model.

Ready to strengthen your understanding?

You've refreshed what you already know. Next, you'll reinforce the essential concepts that will help you solve problems with confidence. Need to see the learning path again?

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Core Concepts

Start with source, center-to-center distance, and direction; then choose force, field, energy, or orbit relationships.

KEY CONCEPT 1

SHM model and cycle relationships

For a spring, F = −kx gives ω = √(k/m) and T = 2π√(m/k). Use x = A cos(ωt + φ), with vₘₐₓ = Aω and aₘₐₓ = Aω².

F = −kx; ω = √(k/m); T = 2π/ω; x = A cos(ωt + φ)

Example: For m = 0.50 kg and k = 200 N/m, ω = 20 rad/s and T ≈ 0.314 s.

Sensei Note: Do not treat amplitude, velocity, and acceleration as quantities that peak at the same location in the cycle.

KEY CONCEPT 2

Energy and standard oscillators

For a spring, E = ½kA² = ½mv² + ½kx². For a small-angle simple pendulum, T ≈ 2π√(L/g). Spring period is amplitude-independent in the ideal model; pendulum amplitude-independence is only approximate at small angle.

E = ½mv² + ½kx² = ½kA²; Tₚ ≈ 2π√(L/g)

Example: For k = 50 N/m and A = 0.10 m, E = 0.25 J.

Sensei Note: Use the small-angle pendulum formula only after checking that the angular amplitude is sufficiently small for the intended accuracy.

Ready to apply these ideas?

You've reinforced the essential concepts. Now it's time to put them into practice by working through guided examples and building your problem-solving confidence. Need a quick reminder?

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Guided Practice

Apply the two highest-leverage methods in short activities. Reveal each solution only after attempting the problem.

PRACTICE 1

Guided Example

Solve one complete spring-cycle model.

A 0.25 kg mass on a 100 N/m spring oscillates with A = 0.040 m. Find T and vₘₐₓ.
Reveal Answer
T = 2π√(0.25/100) ≈ 0.314 s; vₘₐₓ = A√(k/m) = 0.80 m/s.

Why it works: Use the restoring law first, then cycle relations; do not mix turning-point and equilibrium properties.

PRACTICE 2

Independent Check

Use energy or the small-angle pendulum relation.

A spring has k = 60 N/m and A = 0.12 m. Find total energy.
Reveal Answer
E = ½(60)(0.12)² = 0.432 J.

Why it works: Energy is often the fastest route when position and speed are related; the pendulum requires an explicit approximation.

Ready to check your understanding?

You've practiced the essential skills with guidance. Now it's time to solve a few short problems on your own and confirm you're ready to move forward. Need a quick reminder?

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Confidence Check

Complete these two short checks without looking back. Then use the scoring guide to decide your next step.

CONFIDENCE CHECK 1

SHM readiness check

Answer without a calculator.

If m quadruples with k fixed, what happens to T?
Reveal Answer
T doubles.

Why it works: Use a = −ω²x and T ∝ √m for an ideal spring oscillator.

CONFIDENCE CHECK 2

Energy and pendulum check

State one reason with each answer.

Does the ideal spring period depend on amplitude?
Reveal Answer
No.

Why it works: Turning points have v = 0; ideal linear-spring frequency depends on k and m; pendulum SHM requires small-angle linearization.

How did it go?

I answered ___ of 2 questions correctly.

1 correct: You’re ready to continue. 1 correct: Review the missed idea, then continue. 0 correct: Revisit Core Concepts or choose more practice.

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Summary

Before moving on, take one final look at the most important ideas from this review.

KEY TAKEAWAY 1

Restoring law + phase tells the cycle

Verify a ∝ −x, then use ω, T, f, and the x-v-a phase relationships. Turning points: v = 0. Equilibrium: |v| maximum.

KEY TAKEAWAY 2

Energy and approximation choose the model

For ideal springs use E = ½kA². For pendulums, use the SHM period only under the small-angle approximation.

Ready for your next step?

You've reviewed the essential ideas one last time. Now choose the resource that best matches how confident you feel. Need a quick reminder?

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