FULL REVIEW

Full Review: Gravitation — Algebra-Based

Review the essential ideas, relationships, and problem-solving tools for Gravitation.

TIME

45–60 minutes

BEST FOR

A complete topic review

FINISH WITH

A readiness check

After this full review, you'll be able to...

recall the essential ideas, apply them to representative problems, and determine what to study next.

Choose how you want to review

Topic Alignment

This bundle is aligned to the approved Physics Sensei topic specification below. Use it to recover the topic structure, reinforce key decisions, and confirm readiness for the next study task.

 TEXTBOOK: Independent Physics Sensei Unit Review

CHAPTER: Mechanics • MEC-U13

TOPIC: Gravitation

COURSE LEVEL: Algebra-Based

BEST USED

✓ After reading the chapter

✓ Before starting homework

✓ Before a quiz or exam

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Your Review Plan

Complete these six stages in order. Each stage builds on the previous one and prepares you for the final readiness check.

6 Stages • Approximately 45-60 minutes.

Warm-Up Check

Activate prior knowledge.

Core Concepts

Review the essential ideas.

Guided Practice

Apply what you learned.

Confidence Check

Confirm your understanding.

Summary

Review the key ideas.

Next Step

Continue your learning.

Warm-Up Check

Before you begin, take a moment to see what you already remember. Do not worry about getting everything right. This is only a starting point.

ACTIVITY 1

Recall Activity 1

Use proportional reasoning.

If the source mass doubles and separation triples, determine Fnew/Fold.
Reveal Answers
Fnew/Fold = 2/9.

Why it works: Mass contributes linearly; distance contributes through 1/r².

ACTIVITY 2

Recall Activity 2

Classify the quantity and its sign.

For two separated positive masses with U(∞) = 0, is U positive, zero, or negative?
Reveal Answers
Negative.

Why it works: Work must be supplied to separate a bound pair to infinity.

ACTIVITY 3

Recall Activity 3

Set up a circular orbit.

Write the force equation for a mass m in a circular orbit of radius r around dominant mass M.
Reveal Answers
GMm/r² = mv²/r.

Why it works: “Centripetal force” names the required net inward force; it is not an extra force.

Ready to strengthen your understanding?

You've refreshed what you already know. Next, you'll reinforce the essential concepts that will help you solve problems with confidence. Need to see the learning path again?

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Core Concepts

Let's rebuild the key ideas one step at a time. Focus on understanding the relationships before worrying about solving problems.

KEY CONCEPT 1

Force, field, direction, and superposition 1

Use F = Gm₁m₂/r² for a pair, g = GM/r² for a source, and vector components for multiple sources. Add vectors, not magnitudes. For a spherical source and an external point, treat the source as concentrated at its center.

Fg = Gm₁m₂/r²; g = GM/r²; F = m g.

For 5.0×10¹² kg and 8.0×10⁸ kg separated by 2.0×10⁶ m, F = 0.0667 N. Each body experiences this magnitude in the opposite direction.

Lock the model before calculating: identify the source, test object, center-to-center distance, and direction of every contribution.

KEY CONCEPT 2

Potential, potential energy, work, and binding 2

Use U = -GMm/r and V = -GM/r. In an isolated system, K+U is conserved. Near a surface, mgh is only an approximation for height changes small compared with the source radius.

U = -GMm/r; V = -GM/r; Ki+Ui = Kf+Uf.

For M = 6.0×10²⁴ kg and m = 1000 kg moved from 7.0×10⁶ m to 8.0×10⁶ m, ΔU = +7.15×10⁹ J.

Negative U is not “negative energy motion.” K remains nonnegative; the sign of total E classifies whether an ideal two-body orbit is bound.

KEY CONCEPT 3

Circular orbits, escape, and Kepler relationships 3

Set gravity equal to the required net inward force for a circular orbit. Use energy for escape and transfers between radii. Kepler’s laws describe ellipse shape, equal areas in equal times, and T²∝a³.

vc = √(GM/r); T = 2π√(r³/GM); Ec = -GMm/(2r); vesc = √(2GM/r); T² = 4π²a³/(GM).

For M = 6.0×10²⁴ kg and r = 7.0×10⁶ m: vc = 7.56 km/s, T = 5.82×10³ s = 97.0 min, and vesc = 10.7 km/s.

Never use altitude in an orbital formula until you convert it to radius from the center. Never add a separate “centripetal force” to gravity.

Ready to apply these ideas?

You've reinforced the essential concepts. Now it's time to put them into practice by working through guided examples and building your problem-solving confidence. Need a quick reminder?

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Guided Practice

Now it's time to apply what you've reviewed.

Work through each activity in order. The examples become gradually more challenging, and each one prepares you for the final readiness check.

PRACTICE 1

Worked Example

Model the interaction, show direction, and calculate or justify the result.

A point is 3.0 m to the right of a 4.0×10¹² kg mass and 6.0 m to the left of a 9.0×10¹² kg mass. Find the net field.
Reveal Answers
12.97 N/kg toward the 4.0×10¹² kg mass.

Why it works: Left contribution = 29.64 N/kg; right contribution = 16.68 N/kg; net = 12.97 N/kg left.

PRACTICE 2

Guided Problem

Choose an energy reference and solve without using constant-g kinematics.

A 1000 kg spacecraft moves from rest at r₁ = 7.0×10⁶ m to r₂ = 8.0×10⁶ m around M = 6.0×10²⁴ kg. What external work is required if it starts and ends at rest?
Reveal Answers
Wext = ΔU = +7.15×10⁹ J.

Why it works: With zero initial and final kinetic energy, external work equals the potential-energy increase.

PRACTICE 3

Independent Problem

Select the orbital relationship, state assumptions, and check scale.

Calculate circular speed and period for M = 6.0×10²⁴ kg and r = 7.0×10⁶ m using G = 6.67×10⁻¹¹ SI.
Reveal Answers
v = 7.56×10³ m/s; T = 5.82×10³ s≈97.0 min.

Why it works: Set GMm/r² = mv²/r, then use T = 2πr/v.

Ready to check your understanding?

You've practiced the essential skills with guidance. Now it's time to solve a few short problems on your own and confirm you're ready to move forward. Need a quick reminder?

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Confidence Check

You've rebuilt the key ideas and practiced them with guidance. Now try these short questions on your own to check your understanding before moving on.

QUICK CHECK 1

Force or field?

Answer and justify in one sentence.

A source mass doubles while r halves. By what factor does g change?
Reveal Answers
Eight.

Why it works: g∝M/r² gives 2/(1/2)² = 8.

QUICK CHECK 2

Energy sign and motion

Classify the claim.

For a circular orbit, compare K, U, and E.
Reveal Answers
K = +GMm/(2r), U = -GMm/r = -2K, E = -GMm/(2r).

Why it works: Insert v² = GM/r into K = mv²/2.

QUICK CHECK 3

Orbit model check

Choose the valid relationship.

Can v = √(GM/r) be used at every point of an ellipse?
Reveal Answers
No; it is the circular-orbit speed at radius r.

Why it works: Elliptical speed also depends on semimajor axis through the vis-viva relation.

How did it go?

You've checked your understanding. Take one final look at the essential ideas before deciding what to do next. Need a quick reminder?

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Summary

Before moving on, take one final look at the most important ideas from this review.

KEY TAKEAWAY 1

Choose the gravitational quantity

Force depends on source and test masses; field and potential describe the source at a location. Preserve vector direction for force and field.

KEY TAKEAWAY 2

Use the general energy model

With zero at infinity, U = -GMm/r. Use mgh only for small height changes in an approximately uniform field.

KEY TAKEAWAY 3

Orbit means gravity-driven free fall

For a circular orbit, gravity is the net inward force. Radius is measured from the center; escape and general bound orbits are best analyzed with energy.

Ready for your next step?

You've reviewed the essential ideas one last time. Now choose the resource that best matches how confident you feel. Need a quick reminder?

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Next Step

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