🥋 Units, Conversions, and Dimensional Analysis – White to Black Belt Mastery
Intro Quote or Motto
“A measurement without units is like a punch without aim — it has no real meaning.”
Key Concept (White Belt Level)
Units give meaning to numbers. Conversions change a measurement from one unit to another
without changing its value. Dimensional analysis checks whether equations make physical sense.
Throughout this guide, final answers are shown to 3 significant figures (3SF).
Core Principles
- SI base units: meter (m), kilogram (kg), second (s), ampere (A), kelvin (K), mole (mol), candela (cd).
- Common derived units: newton (N = kg·m/s²), joule (J = N·m), watt (W = J/s), pascal (Pa = N/m²).
- Prefixes: milli (m, 10⁻³), micro (µ, 10⁻⁶), kilo (k, 10³), mega (M, 10⁶), giga (G, 10⁹).
- Factor–label method: multiply by conversion factors that equal 1 so units cancel cleanly.
- Dimensional analysis: both sides of an equation must match in dimensions (e.g., [M], [L], [T]).
Common Mistakes and Pitfalls
- Mixing unit systems (e.g., m with km) without converting first.
- Dropping units during steps; always carry and cancel them visibly.
- Rounding too early — keep guard digits, then round the final answer to 3SF.
- Using formulas that aren’t dimensionally consistent.
Sensei’s Shortcuts
- Write units on every line; let them guide each operation.
- Convert prefixes first (e.g., km → m) before other calculations.
- If dimensions don’t match, fix the algebra before plugging in numbers.
- Sanity-check magnitudes: does the result look reasonable?
Worked Example – Step by Step (White Belt)
Problem. Convert 65.0 km/h to m/s, and convert 2.50 h to seconds. Report 3SF.
Solution.
Speed: 65.0 km/h × (1000 m / 1 km) × (1 h / 3600 s) = 18.1 m/s.
Time: 2.50 h × (3600 s / 1 h) = 9.00 × 10³ s.
Final Answer: 18.1 m/s; 9.00 × 10³ s.
Practice Drill
- Convert 3.60 km/min to m/s.
- Convert 45.0 m/s to km/h.
- Convert 3.50 g/cm³ to kg/m³.
Answers
- 60.0 m/s
- 162 km/h
- 3.50 × 10³ kg/m³
Yellow Belt Extension – Deeper Skills
Dimensional check: s = u t + 0.5 a t²
- u t ⇒ (L·T⁻¹)·T = L
- a t² ⇒ (L·T⁻²)·T² = L
- Sum gives L, matching s (length).
Pendulum scaling via dimensions. Suppose period T depends on length L and g:
Assume T ∝ L^α g^β. Dimensions: [T] = [L]^α [L·T⁻²]^β = L^{α+β} T^{−2β}.
Match exponents ⇒ −2β = 1 ⇒ β = −1/2; α + β = 0 ⇒ α = 1/2 ⇒
T ∝ √(L/g).
Black Belt Mastery – Exam Strategy and Challenge
Challenge.
- A cyclist rides at 27.8 m/s. Convert to mph.
- Pressure is 1.02 × 10⁵ Pa. Convert to kPa and to atm (1 atm = 1.013 × 10⁵ Pa).
- Someone claims power = force × distance. Use dimensions to accept or reject this.
Sensei Strategy Notes
- Chain factors for (1): m→km→mi and s→h.
- For (2), Pa → kPa (÷1000) and compare to atm.
- Power should be force × velocity; check dimensions.
Suggested Answers (3SF)
- 27.8 m/s × 3.60 km/h per m/s ÷ 1.61 km/mi = 62.2 mph (approx).
- 1.02 × 10⁵ Pa = 102 kPa; (1.02 × 10⁵) / (1.013 × 10⁵) = 1.01 atm.
- [Force × distance] = (M·L·T⁻²)·L = M·L²·T⁻² (work), not power (M·L²·T⁻³). Correct relation: power = force × velocity.
Sensei’s Final Words
“Units are your stance, conversions your footwork, and dimensional analysis your guard. Master them, and every calculation lands clean.”